I believe pressure takes the path of least resistance. An over pressured shell must reach catastrophic pressures to blow a chamber instead of passing down the barrel. I'm not saying there would not be damage but without a barrel obstruction how much pressure is required to blow a breach otherwise? Without a compromised barrel it must be tremendously over SAAMI pressures? Now I am not an engineer but I am a generalist who works with engineers daily, the logic prevails me. Perhaps those who understand ballistic pressures can explain.

Nothing is foolproof to a sufficiently talented fool.