Weight reduction for back boring: assume steel has 4.16 oz/cubic inch, ID = 0.655 so circumference (pi X D) = 2.06", for 30" bbls assume you can bore 26" (chamber @ 2 3/4" + cone @ 1 1/4"), bore area = 26" X 2.06" = 53.5 sq inches. Removed volume per thousandth = 53.5 in sq X 0.001" = 0.05 in cubed, removed weight per thousandth per barrel = 0.05 in cubed X 4.16 oz/in cubed = 0.22 oz --- say 1/4 oz per thousandth back bore per barrel. Going from 0.655 to 0.662 = 7 thousandths X 1/4 oz per thousandth X 2 barrels = 3.5 oz.
Questions?
That's pretty amazing and that would indeed drop her down to where she needs to be. Thanks.
